Negative Immittance Converters#
Negative immittance converters (NICs) are circuits capable of transferring the voltage and current of an electronic component, whilst reversing the direction of one or the other and potentially scaling them:
- A negative immittance converter which reverses the direction of current, whilst retaining the direction of voltage, is known as a current inversion negative immittance converter (INIC);
- A negative immittance converter which reverses the direction of voltage, whilst retaining the direction of current, is known as a voltage inversion negative immittance converter (VNIC).
Negative immittance converters are extremely useful because they can be used for many purposes:
- Reversing the current or voltage direction results in the reversal of the sign of the resistance / conductance (both static and dynamic) of the electronic component. This allows us to physically realize resistors with negative resistance.
TODO
Theoretical Model#
Definition: Negative Immittance Converter
A negative immittance converter is a two-port whose I-V characteristic is
for some constant \(k \in \mathbb{R}_{\ne 0}\) known as the conversion ratio.
A negative immittance converter is:
Theorem: Implicit Representations
If a negative immittance converter has a conversion ratio \(k\), then
is an implicit representation of it.
Proof
TODO
Theorem: Explicit Representations
The negative immittance converter has neither an admittance representation nor an impedance representation.
It has the following hybrid representation and inverse hybrid representation:
It has the following forwards transmission representation and backwards transmission representation:
Proof
TODO
Theorem: Antireciprocity of NICs
Negative immittance converter are always antireciprocal.
Proof
TODO
Theorem: Symmetry Condition for NICs
A negative immittance converter is symmetrical if and only if \(|k| = 1\).
Proof
TODO
Implementation#
Example: INIC from Nullor
A INIC can be constructed using a nullor and two identical Ohmic resistors:
The voltage across the nullator is zero and so Kirchhoff's voltage law gives us the following:
Similarly, applying Kirchhoff's voltage law to the nullator and the two Ohmic resistors, we get that \(R i_1 = R i_2\). We therefore have:
We have obtained the equations of a negative immittance converter
with \(k = -1\).
TODO FIX
Example: VNIC from Nullor
A VNIC be constructed using a nullor and two identical Ohmic resistors:
The voltage across the nullator is zero and so Kirchhoff's voltage law gives us the following:
Similarly, there is no current flowing through the nullator and so the two Ohmic resistors and the norator form a parallel circuit. This immediately makes them a one-port and we get the following:
We therefore obtain the equations of a negative immittance converter
$$
\left\vert\begin{aligned}v_1 &= -k v_2 \ i_1 &= -\frac{1}{k} i_2 \end{aligned}\right.$$
with \(k = +1\).
TODO FIX
Example: NIC from Op-Amp
A negative immittance converter can be constructed using an ideal operational amplifier and Ohmic resistors:
As long as the ideal op-amp is operated in its linear region, the above circuit behaves like a negative immittance converter with \(k = -1\).
To ensure that the ideal op-amp is indeed operated in its linear region, we need to have \(v_1 - R i_1 \in [-V_{\text{sat}}; +V_{\text{sat}}]\).
We can see this by analyzing the network.
Linear region:
When the ideal op-amp is operated in its linear region, we know that it is equivalent to a nullor. In this case, it would be connected in such a way so as to act as a NIC with \(k = -1\)
Saturation regions:
When the ideal op-amp is operated outside its linear region, we know that \(v_d \ne 0\). The differential voltage is given by \(v_d = v_+ - v_- = v_2 - v_1\).
According to Kirchhoff's voltage law, the relationships between the port voltages and currents still hold:
By substituting these into the expression for \(v_d\), we can determine the saturation conditions based on the currents:
When the ideal op-amp is operated in its negative saturation region, we have \(v_d \lt 0\) and \(v_{\text{out}} = -V_{\text{sat}}\):
In this state, the voltage at port 1 is clamped relative to the current:
By contrast, when the ideal op-amp is operated in its positive saturation region, we have \(v_d \gt 0\) and \(v_{\text{out}} = +V_{\text{sat}}\):
In this state, the voltage at port 1 is clamped as follows: